wildtype<- c(103,1125,504,608,794,698,920,535,842,765,945,1005,724,498,727)
print(wildtype) [1] 103 1125 504 608 794 698 920 535 842 765 945 1005 724 498 727
Hafez Ahmad
October 16, 2022
You will find basic R codes
[1] 103 1125 504 608 794 698 920 535 842 765 945 1005 724 498 727
#2. Create variable called “resistant”—-
resistant<- c(768, 230, 854 ,637,426, 482, 1118, 524, 604 ,730 ,17 ,421, 587, 782 ,171)
print(resistant) [1] 768 230 854 637 426 482 1118 524 604 730 17 421 587 782 171
#3. combine the the vectors into data frame called “miner”—-
wild resist
1 103 768
2 1125 230
3 504 854
4 608 637
5 794 426
6 698 482
7 920 1118
8 535 524
9 842 604
10 765 730
11 945 17
12 1005 421
13 724 587
14 498 782
15 727 171
#4. Calculate the mean and variance of the wildtype and resistant from the data frame “miner”—-
print(paste0("The mean of wildtype is ",round(x=mean(miner$wild),digits=3)," and the variance is ",round(x=var(miner$wild),digits=3)))[1] "The mean of wildtype is 719.533 and the variance is 63014.552"
print(paste0("The mean of resistant is ",round(x=mean(miner$resist),digits=3)," and the variance is ",round(x=var(miner$resist),digits=3)))[1] "The mean of resistant is 556.733 and the variance is 80529.21"
formula for standard error is standard deviation/square root ($ {(n)}$) of sample size
#…apply the function to the data frame “miner”—-
[1] "The standard error of wildtype is 64.815"
[1] "The standard error of resistant is 73.271"
#6. write a function for growth rate called “rate” —-
where, nt is the vector abunace at t,ntplus the vector of abunance at year t+1 and t for vector of years and return plot for growth rate … load data from laptop